What is the critical f(x)=(x^2-3)e^{-x} ?

The critical f(x)=(x^2-3)e^{-x} is x=-1,x=3

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critical f(x)=(x^2-3)e^{-x}

critical points

f (x) = (x^{2} - 3) e^{- x}

x = - 1, x = 3

Solution steps

(x^{2} - 3) e^{- x}

Find where

f^{'} (x)

is equal to zero or undefined

x = - 1, x = 3

Identify critical points not in

f (x)

domain

Domain of

(x^{2} - 3) e^{- x} : - \infty < x < \infty

All critical points are in domain

x = - 1, x = 3

f (x) = - 2 x^{3} + 33 x^{2} - 108 x + 11

f (x) = x y + \frac{2}{x} + \frac{4}{y}

f (x) = cos (\frac{2 π}{3} x)

f (x) = 12 x^{5} + 30 x^{4} - 160 x^{3} + 7

f (x) = - 3 x^{4} + 20 x^{3} - 17

What is the critical f(x)=(x^2-3)e^{-x} ?
The critical f(x)=(x^2-3)e^{-x} is x=-1,x=3