What is the critical f(x)=(x^2)/(x^2-64) ?

The critical f(x)=(x^2)/(x^2-64) is x=0

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

critical f(x)=(x^2)/(x^2-64)

critical points

f (x) = \frac{x ^{2}}{x ^{2} - 64}

x = 0

Solution steps

\frac{x ^{2}}{x ^{2} - 64}

Find where

f^{'} (x)

is equal to zero or undefined

x = 0, x = - 8, x = 8

Identify critical points not in

f (x)

domain

Domain of

\frac{x ^{2}}{x ^{2} - 64} : x < - 8 or - 8 < x < 8 or x > 8

\frac{x ^{2}}{x ^{2} - 64}

is not defined at

x = - 8, x = 8

, therefore:

x = 0

f (x, y) = x^{3} + 3 x y^{2} - 6 x y + 1

f (x) = \frac{( x + 1 )}{x ^{2}}

x^{2} + 6

f (x) = x^{3} - 2 x y + y^{2} + 3

f (x) = 2 x + \frac{128}{x}

What is the critical f(x)=(x^2)/(x^2-64) ?
The critical f(x)=(x^2)/(x^2-64) is x=0