What is the critical f(x)=(9x^2ln(x)) ?

The critical f(x)=(9x^2ln(x)) is x= 1/(sqrt(e))

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critical f(x)=(9x^2ln(x))

critical points

f (x) = (9 x^{2} ln (x))

x = \frac{1}{e}

Solution steps

9 x^{2} ln (x)

Find where

f^{'} (x)

is equal to zero or undefined

x = \frac{1}{e}, x = 0

Identify critical points not in

f (x)

domain

Domain of

9 x^{2} ln (x) : x > 0

9 x^{2} ln (x)

is not defined at

x = 0

, therefore:

x = \frac{1}{e}

\frac{x ^{3} + 1}{x ^{2}}

f (x) = x^{\frac{2}{3}} (x^{2} - 8)

f (x) = ln (x) + ln (64 - x^{2})

ln (1 - ln (x))

f (x) = x^{\frac{2}{3}} (x^{2} - 9)

What is the critical f(x)=(9x^2ln(x)) ?
The critical f(x)=(9x^2ln(x)) is x= 1/(sqrt(e))