What is the perpendicular y=-5/7 x+11/7 ,(5,-2) ?

The perpendicular y=-5/7 x+11/7 ,(5,-2) is y= 7/5 x-9

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perpendicular y=-5/7 x+11/7 ,(5,-2)

perpendicular

y = - \frac{5}{7} x + \frac{11}{7}, (5, - 2)

y = \frac{7}{5} x - 9

Solution steps

Find the line

y = mx + b

perpendicular to

y = - \frac{5}{7} x + \frac{11}{7}

that passes through

(5, - 2)

Find the slope of

y = - \frac{5}{7} x + \frac{11}{7} : m = - \frac{5}{7}

Compute the slope of the perpendicular line:

m_{p} = \frac{7}{5}

Find the line with slope m=

\frac{7}{5}

and passing through

(5, - 2) : y = \frac{7}{5} x - 9

y = \frac{7}{5} x - 9

\frac{1}{3 x - 2}

f (x) = y^{2} + x - 9 = 0

X + 3

f (x) = x^{2} - 4 x - 7

4 x - 2 y = - 8

What is the perpendicular y=-5/7 x+11/7 ,(5,-2) ?
The perpendicular y=-5/7 x+11/7 ,(5,-2) is y= 7/5 x-9