What is the critical f(x)=(x^3)/3-ln(x) ?

The critical f(x)=(x^3)/3-ln(x) is x=1

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critical f(x)=(x^3)/3-ln(x)

critical points

f (x) = \frac{x ^{3}}{3} - ln (x)

x = 1

Solution steps

\frac{x ^{3}}{3} - ln (x)

Find where

f^{'} (x)

is equal to zero or undefined

x = 1, x = 0

Identify critical points not in

f (x)

domain

Domain of

\frac{x ^{3}}{3} - ln (x) : x > 0

\frac{x ^{3}}{3} - ln (x)

is not defined at

x = 0

, therefore:

x = 1

y = \frac{x ^{2} + 2}{2 x - 1}

f (x) = x^{3} + 9 x^{2} + b

x^{\frac{8}{3}} - 8 x^{\frac{1}{3}}

f (x) = x^{3} + 3 x^{2} y - 3 x y^{2} + y^{3}

e^{- x} x^{2} + e^{- x}

What is the critical f(x)=(x^3)/3-ln(x) ?
The critical f(x)=(x^3)/3-ln(x) is x=1