What is the inflection (x^3-1)/(x^3+1) ?

The inflection (x^3-1)/(x^3+1) is (0,-1),(1/(\sqrt[3]{2)},-1/3)

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inflection (x^3-1)/(x^3+1)

inflection points

\frac{x ^{3} - 1}{x ^{3} + 1}

Solution steps

f^{''} (x) = \frac{12 x ( - 2 x ^{3} + 1 )}{( x ^{3} + 1 ) ^{3}}

Find intervals:

Concave Upward

: - \infty < x < - 1,

Concave Downward

: - 1 < x < 0,

Concave Upward

Concave Downward

Plug

x = 0

into

\frac{x ^{3} - 1}{x ^{3} + 1} : - 1

(0, - 1)

Plug

into

\frac{x ^{3} - 1}{x ^{3} + 1} : - \frac{1}{3}

f (x) = n^{3} - 5

y = - \frac{1}{2} x + 3, (3, 6)

f (x) = 3 x - 3

y = - \frac{x}{4} - 5, (7, - 3)

f (x) = \frac{1}{x ^{2} + 4} - \frac{1}{x ^{2} - 4}

What is the inflection (x^3-1)/(x^3+1) ?
The inflection (x^3-1)/(x^3+1) is (0,-1),(1/(\sqrt[3]{2)},-1/3)