What is the critical f(x)=(x-4)e^{-3x} ?

The critical f(x)=(x-4)e^{-3x} is x= 13/3

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critical f(x)=(x-4)e^{-3x}

critical points

f (x) = (x - 4) e^{- 3 x}

x = \frac{13}{3}

Solution steps

(x - 4) e^{- 3 x}

Find where

f^{'} (x)

is equal to zero or undefined

x = \frac{13}{3}

Identify critical points not in

f (x)

domain

Domain of

(x - 4) e^{- 3 x} : - \infty < x < \infty

All critical points are in domain

x = \frac{13}{3}

f (x) = ∣ sin (x) ∣, 0 < x < 2 π

\frac{2 x ^{2} + 1}{x ^{2} - 1}

2 x^{3} + 12 x^{2} + 18 x

f (x) = 9 x^{2} ln (x)

x^{3} + y^{3} + 3 x y + 5

What is the critical f(x)=(x-4)e^{-3x} ?
The critical f(x)=(x-4)e^{-3x} is x= 13/3