What is the critical f(x)=(x^2+4)/(2x) ?

The critical f(x)=(x^2+4)/(2x) is x=-2,x=2

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critical f(x)=(x^2+4)/(2x)

critical points

f (x) = \frac{x ^{2} + 4}{2 x}

x = - 2, x = 2

Solution steps

\frac{x ^{2} + 4}{2 x}

Find where

f^{'} (x)

is equal to zero or undefined

x = - 2, x = 2, x = 0

Identify critical points not in

f (x)

domain

Domain of

\frac{x ^{2} + 4}{2 x} : x < 0 or x > 0

\frac{x ^{2} + 4}{2 x}

is not defined at

x = 0

, therefore:

x = - 2, x = 2

f (x) = 4 x^{3} + \frac{11}{2} x^{2} - 15 x

\frac{d}{d I} (e^{x} I n x)

f (x) = (x - 2)^{2} (x + 6)

f (x) = sin (x) + sin^{3} (x)

f (x) = x^{3} - 3 x + 8

What is the critical f(x)=(x^2+4)/(2x) ?
The critical f(x)=(x^2+4)/(2x) is x=-2,x=2