What is the critical f(x)=3x+1/x ?

The critical f(x)=3x+1/x is x=-1/(sqrt(3)),x= 1/(sqrt(3))

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critical f(x)=3x+1/x

critical points

f (x) = 3 x + \frac{1}{x}

x = - \frac{1}{3}, x = \frac{1}{3}

Solution steps

3 x + \frac{1}{x}

Find where

f^{'} (x)

is equal to zero or undefined

x = - \frac{1}{3}, x = \frac{1}{3}, x = 0

Identify critical points not in

f (x)

domain

Domain of

3 x + \frac{1}{x} : x < 0 or x > 0

3 x + \frac{1}{x}

is not defined at

x = 0

, therefore:

x = - \frac{1}{3}, x = \frac{1}{3}

f (x) = 3 x^{4} + 8 x^{3} - 6 x^{2} - 24 x

f (x) = 4 x^{\frac{1}{2}} - 2 x

f (x) = x + ln (x)

f (x) = 2.2 + 4.2 x - 1.6 x^{2}

f (x) = 3 x^{2} - 2 x - 6

What is the critical f(x)=3x+1/x ?
The critical f(x)=3x+1/x is x=-1/(sqrt(3)),x= 1/(sqrt(3))