What is the critical f(x)= 4/3 x^{-2/3}(x-1) ?

The critical f(x)= 4/3 x^{-2/3}(x-1) is x=-2

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critical f(x)= 4/3 x^{-2/3}(x-1)

critical points

f (x) = \frac{4}{3} x^{- \frac{2}{3}} (x - 1)

x = - 2

Solution steps

\frac{4}{3} x^{- \frac{2}{3}} (x - 1)

Find where

f^{'} (x)

is equal to zero or undefined

x = - 2, x = 0

Identify critical points not in

f (x)

domain

Domain of

\frac{4}{3} x^{- \frac{2}{3}} (x - 1) : x < 0 or x > 0

\frac{4}{3} x^{- \frac{2}{3}} (x - 1)

is not defined at

x = 0

, therefore:

x = - 2

f (x) = 2 x^{3} + 3 x^{2} - 72 x - 9

x^{\frac{2}{3}} (3 - x)

\frac{d}{d x} (\frac{7 x ^{3} y}{x - 4 y})

f (x) = 2 cos (x) - 2 sin (x)

f (x) = \frac{x + 3}{x ^{2} - 5 x + 6}

What is the critical f(x)= 4/3 x^{-2/3}(x-1) ?
The critical f(x)= 4/3 x^{-2/3}(x-1) is x=-2