What is the inverse of f(x)=(1/4)^{(x+3)}-4 ?

The inverse of f(x)=(1/4)^{(x+3)}-4 is -(ln(x+4))/(2ln(2))-3

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inverse of f(x)=(1/4)^{(x+3)}-4

inverse

f (x) = (\frac{1}{4})^{(x + 3)} - 4

- \frac{ln ( x + 4 )}{2 ln ( 2 )} - 3

Solution steps

y = (\frac{1}{4})^{x + 3} - 4

Replace

x

with

y

x = (\frac{1}{4})^{y + 3} - 4

Solve for

y, x = (\frac{1}{4})^{y + 3} - 4

- \frac{ln ( x + 4 )}{2 ln ( 2 )} - 3

x^{3} - 3 x^{2}

f (x) = \frac{x ^{2} - 2 x + 2}{x - 1}

f (x) = \frac{- 2}{( x - 3 ) ^{2}}

y = e^{x - 3}

f (x) = (\frac{x}{4} - (\frac{1}{4}))^{\frac{1}{3}}

What is the inverse of f(x)=(1/4)^{(x+3)}-4 ?
The inverse of f(x)=(1/4)^{(x+3)}-4 is -(ln(x+4))/(2ln(2))-3