What is the critical f(x)=14sqrt(10pix)+(160)/x ?

The critical f(x)=14sqrt(10pix)+(160)/x is x=(8\sqrt[3]{5})/(\sqrt[3]{49)\sqrt[3]{pi}}

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critical f(x)=14sqrt(10pix)+(160)/x

critical points

f (x) = 14 10 π x + \frac{160}{x}

x = \frac{8 3 5}{3 49 3 π}

Solution steps

14 10 π x + \frac{160}{x}

Find where

f^{'} (x)

is equal to zero or undefined

x = \frac{8 3 5}{3 49 3 π}, x = 0

Identify critical points not in

f (x)

domain

Domain of

14 10 π x + \frac{160}{x} : x > 0

14 10 π x + \frac{160}{x}

is not defined at

x = 0

, therefore:

x = \frac{8 3 5}{3 49 3 π}

f (x, y) = x + y - 1

f (x) = I n (2 x + 1)

\frac{2 x}{x ^{2} + 9} - 1

- 3 x^{4} + 5 x^{2} + 3

y = - x^{3} + 3 x^{2}

What is the critical f(x)=14sqrt(10pix)+(160)/x ?
The critical f(x)=14sqrt(10pix)+(160)/x is x=(8\sqrt[3]{5})/(\sqrt[3]{49)\sqrt[3]{pi}}