What is the inflection f(x)=ln(x^2+9) ?

The inflection f(x)=ln(x^2+9) is (-3,ln(18)),(3,ln(18))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

inflection f(x)=ln(x^2+9)

inflection points

f (x) = ln (x^{2} + 9)

(- 3, ln (18)), (3, ln (18))

Solution steps

f^{''} (x) = \frac{2 ( - x ^{2} + 9 )}{( x ^{2} + 9 ) ^{2}}

Find intervals:

Concave Downward

: - \infty < x < - 3,

Concave Upward

: - 3 < x < 3,

Concave Downward

: 3 < x < \infty

Plug

x = - 3

into

ln (x^{2} + 9) : ln (18)

(- 3, ln (18))

Plug

x = 3

into

ln (x^{2} + 9) : ln (18)

(3, ln (18))

(- 3, ln (18)), (3, ln (18))

m = 0, (- 2, 2)

f (x) = 2 x + 12

f (x) = \frac{2 x + 1}{5}

(- 7, - 4), (- 2, 3)

f (x) = \frac{63}{x ^{2} + 8 x + 15}

What is the inflection f(x)=ln(x^2+9) ?
The inflection f(x)=ln(x^2+9) is (-3,ln(18)),(3,ln(18))