What is the critical f(x)=3x+8x^{-1} ?

The critical f(x)=3x+8x^{-1} is x=-(2sqrt(2))/(sqrt(3)),x=(2sqrt(2))/(sqrt(3))

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critical f(x)=3x+8x^{-1}

critical points

f (x) = 3 x + 8 x^{- 1}

x = - \frac{2 2}{3}, x = \frac{2 2}{3}

Solution steps

3 x + 8 x^{- 1}

Find where

f^{'} (x)

is equal to zero or undefined

x = - \frac{2 2}{3}, x = \frac{2 2}{3}, x = 0

Identify critical points not in

f (x)

domain

Domain of

3 x + 8 x^{- 1} : x < 0 or x > 0

3 x + 8 x^{- 1}

is not defined at

x = 0

, therefore:

x = - \frac{2 2}{3}, x = \frac{2 2}{3}

f (x) = \frac{x - 3}{e ^{x}}

f (x) = - 3 x^{4} - 16 x^{3} - 24 x^{2} + 13

f (x) = ∣ x + 3 ∣ - 1

\frac{e ^{x}}{e ^{x} + 2}

e^{4 y - x^{2} - y^{2}}

What is the critical f(x)=3x+8x^{-1} ?
The critical f(x)=3x+8x^{-1} is x=-(2sqrt(2))/(sqrt(3)),x=(2sqrt(2))/(sqrt(3))