What is the critical f(x)=((x^{2-1}))/((2x+1)) ?

The critical f(x)=((x^{2-1}))/((2x+1)) is None

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critical f(x)=((x^{2-1}))/((2x+1))

critical points

f (x) = \frac{( x ^{2 - 1} )}{( 2 x + 1 )}

None

Solution steps

\frac{x ^{2 - 1}}{2 x + 1}

Find where

f^{'} (x)

is equal to zero or undefined

x = - \frac{1}{2}

Identify critical points not in

f (x)

domain

Domain of

\frac{x ^{2 - 1}}{2 x + 1} : x < - \frac{1}{2} or x > - \frac{1}{2}

\frac{x ^{2 - 1}}{2 x + 1}

is not defined at

x = - \frac{1}{2}

, therefore:

None

- 0.5 x^{2} + 0.3 x

f (x) = 1 - x^{2}

f (x) = - 5 x^{2} + 6 x + 7

3 x^{4} - 6 x^{2} + 2

4 x^{2} e^{- 2 x} (x^{2} - 4 x + 3)

What is the critical f(x)=((x^{2-1}))/((2x+1)) ?
The critical f(x)=((x^{2-1}))/((2x+1)) is None