What is the critical f(x)= 1/3 x^3-2x^2-12x ?

The critical f(x)= 1/3 x^3-2x^2-12x is x=-2,x=6

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critical f(x)= 1/3 x^3-2x^2-12x

critical points

f (x) = \frac{1}{3} x^{3} - 2 x^{2} - 12 x

x = - 2, x = 6

Solution steps

\frac{1}{3} x^{3} - 2 x^{2} - 12 x

Find where

f^{'} (x)

is equal to zero or undefined

x = - 2, x = 6

Identify critical points not in

f (x)

domain

Domain of

\frac{1}{3} x^{3} - 2 x^{2} - 12 x : - \infty < x < \infty

All critical points are in domain

x = - 2, x = 6

4 x - x^{2}

f (x) = 12 x^{5} + 45 x^{4} - 200 x^{3} + 3

f (x) = - \frac{2 x ^{3}}{3} - \frac{x ^{2}}{2} - x

f (x, y) = 3 x y^{2} + x^{3} - 3 x

f (x) = (6 - x) (x + 1)^{2}

What is the critical f(x)= 1/3 x^3-2x^2-12x ?
The critical f(x)= 1/3 x^3-2x^2-12x is x=-2,x=6