What is the critical f(x)=x^2-6x+4ln(x) ?

The critical f(x)=x^2-6x+4ln(x) is x=1,x=2

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critical f(x)=x^2-6x+4ln(x)

critical points

f (x) = x^{2} - 6 x + 4 ln (x)

x = 1, x = 2

Solution steps

x^{2} - 6 x + 4 ln (x)

Find where

f^{'} (x)

is equal to zero or undefined

x = 1, x = 2, x = 0

Identify critical points not in

f (x)

domain

Domain of

x^{2} - 6 x + 4 ln (x) : x > 0

x^{2} - 6 x + 4 ln (x)

is not defined at

x = 0

, therefore:

x = 1, x = 2

f (x) = x^{2} - 5 x - 6

f (x) = x^{3} - 3 x^{2} - 6 x

f (x, y) = - 216 x + 2 x^{3} + 6 x y^{2} - 3 y^{3}

f (x) = - x^{4} + 8 x^{3}

f (x) = x^{3} e^{- x}

What is the critical f(x)=x^2-6x+4ln(x) ?
The critical f(x)=x^2-6x+4ln(x) is x=1,x=2