What is the critical (x^2-5)/(x-3) ?

The critical (x^2-5)/(x-3) is x=1,x=5

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critical (x^2-5)/(x-3)

critical points

\frac{x ^{2} - 5}{x - 3}

x = 1, x = 5

Solution steps

\frac{x ^{2} - 5}{x - 3}

Find where

f^{'} (x)

is equal to zero or undefined

x = 1, x = 5, x = 3

Identify critical points not in

f (x)

domain

Domain of

\frac{x ^{2} - 5}{x - 3} : x < 3 or x > 3

\frac{x ^{2} - 5}{x - 3}

is not defined at

x = 3

, therefore:

x = 1, x = 5

f (x, y) = 2 x^{3} + 2 y^{3} - 6 x y

y = ∣ 3 t - 4 ∣

f (x) = \frac{- 3 x + 8}{2 4 - x}

8 x^{2} + 8 x y + 10 y^{2} - 24 x - 28 y + 27

f (x, y) = x^{3} + y^{4}