What is the critical (5x^2-20x)/(2sqrt(x+5)) ?

The critical (5x^2-20x)/(2sqrt(x+5)) is x=(2(sqrt(46)-4))/3

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critical (5x^2-20x)/(2sqrt(x+5))

critical points

\frac{5 x ^{2} - 20 x}{2 x + 5}

x = \frac{2 ( 46 - 4 )}{3}

Solution steps

\frac{5 x ^{2} - 20 x}{2 x + 5}

Find where

f^{'} (x)

is equal to zero or undefined

x = \frac{2 ( 46 - 4 )}{3}, x = - 5

Identify critical points not in

f (x)

domain

Domain of

\frac{5 x ^{2} - 20 x}{2 x + 5} : x > - 5

\frac{5 x ^{2} - 20 x}{2 x + 5}

is not defined at

x = - 5

, therefore:

x = \frac{2 ( 46 - 4 )}{3}

f (x) = 2 x^{2} + 6 x

\frac{x ^{2}}{( x - 2 ) ^{2}}

f (x) = x y^{2} + x^{2} + y

f (x) = - x^{4} + 2 x^{3} + 8 x

f (x) = x^{2} + 4 x - 12

What is the critical (5x^2-20x)/(2sqrt(x+5)) ?
The critical (5x^2-20x)/(2sqrt(x+5)) is x=(2(sqrt(46)-4))/3