What is the critical f(x,y)=(x-3)^2+2y^2 ?

The critical f(x,y)=(x-3)^2+2y^2 is (3,0)

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critical f(x,y)=(x-3)^2+2y^2

critical points

f (x, y) = (x - 3)^{2} + 2 y^{2}

(3, 0)

Solution steps

(x - 3)^{2} + 2 y^{2}

Find where

\nabla f (x, y)

is equal to zero or undefined

(3, 0)

f (x) = 1 + \frac{1}{x}

3 x^{2} + 4 x - 15

\frac{x + 1}{x - 1}

f (x) = f (x, y) = 6 x - x^{2} - 3 x y^{2}

f (x, y) = x y - 5 x - 5 y - x^{2} - y^{2}

What is the critical f(x,y)=(x-3)^2+2y^2 ?
The critical f(x,y)=(x-3)^2+2y^2 is (3,0)