What is the critical (x^3)/(x+1) ?

The critical (x^3)/(x+1) is x=-3/2 ,x=0

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critical (x^3)/(x+1)

critical points

\frac{x ^{3}}{x + 1}

x = - \frac{3}{2}, x = 0

Solution steps

\frac{x ^{3}}{x + 1}

Find where

f^{'} (x)

is equal to zero or undefined

x = - \frac{3}{2}, x = 0, x = - 1

Identify critical points not in

f (x)

domain

Domain of

\frac{x ^{3}}{x + 1} : x < - 1 or x > - 1

\frac{x ^{3}}{x + 1}

is not defined at

x = - 1

, therefore:

x = - \frac{3}{2}, x = 0

f (x) = \frac{e ^{x}}{( 5 x )}, x > 0

f (x) = \frac{x}{x ^{3} - 1}

\frac{8 x - 3}{x}

f (x) = \frac{1}{x + 14}

f (x) = \frac{- 3 x + 27}{x - 8}