What is the critical f(x,y)=xy+ln(x)+8y^2 ?

The critical f(x,y)=xy+ln(x)+8y^2 is (-4, 1/4),(4,-1/4)

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critical f(x,y)=xy+ln(x)+8y^2

critical points

f (x, y) = x y + ln (x) + 8 y^{2}

(- 4, \frac{1}{4}), (4, - \frac{1}{4})

Solution steps

x y + ln (x) + 8 y^{2}

Find where

\nabla f (x, y)

is equal to zero or undefined

(- 4, \frac{1}{4}), (4, - \frac{1}{4})

f (x) = (x + 1)^{3}

f (x) = (5 - 2 x)^{4} + 8

f (x) = 2 x^{3} + x y^{2} + 5 x^{2} + y^{2}

f (x) = I n (2 - x)

f (x, y) = 2 x^{3} - 6 x + 6 x y^{2}

What is the critical f(x,y)=xy+ln(x)+8y^2 ?
The critical f(x,y)=xy+ln(x)+8y^2 is (-4, 1/4),(4,-1/4)