What is the critical ((x^2+1))/((x^2-1)) ?

The critical ((x^2+1))/((x^2-1)) is x=0

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critical ((x^2+1))/((x^2-1))

critical points

\frac{( x ^{2} + 1 )}{( x ^{2} - 1 )}

x = 0

Solution steps

\frac{x ^{2} + 1}{x ^{2} - 1}

Find where

f^{'} (x)

is equal to zero or undefined

x = 0, x = - 1, x = 1

Identify critical points not in

f (x)

domain

Domain of

\frac{x ^{2} + 1}{x ^{2} - 1} : x < - 1 or - 1 < x < 1 or x > 1

\frac{x ^{2} + 1}{x ^{2} - 1}

is not defined at

x = - 1, x = 1

, therefore:

x = 0

y = e^{x^{2} - 5 x - 1}, - 5 \leq x \leq 5

f (x) = \frac{3 x}{x ^{2} - 1}

f (x) = 4 (x - 2)^{\frac{2}{3}}

f (x) = \frac{x + 3}{x - 3}

What is the critical ((x^2+1))/((x^2-1)) ?
The critical ((x^2+1))/((x^2-1)) is x=0