What is the critical f(x,y)=(x^4)/4+(y^4)/4 ?

The critical f(x,y)=(x^4)/4+(y^4)/4 is (0,0)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

critical f(x,y)=(x^4)/4+(y^4)/4

critical points

f (x, y) = \frac{x ^{4}}{4} + \frac{y ^{4}}{4}

(0, 0)

Solution steps

\frac{x ^{4}}{4} + \frac{y ^{4}}{4}

Find where

\nabla f (x, y)

is equal to zero or undefined

(0, 0)

f (x) = x e^{- 5 x}

f (x) = - 216 \cdot x + 2 \cdot x^{3} + 6 \cdot x \cdot y^{2} - 3 \cdot y^{2}

f (x) = (\frac{x + 2}{x - 3})

\frac{x ^{2} + 2}{x ^{2} - 4}

f (x) = x^{2} y - x y^{2}

What is the critical f(x,y)=(x^4)/4+(y^4)/4 ?
The critical f(x,y)=(x^4)/4+(y^4)/4 is (0,0)