What is the critical f(x)=(1-x)/((x+1)^3) ?

The critical f(x)=(1-x)/((x+1)^3) is x=2

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critical f(x)=(1-x)/((x+1)^3)

critical points

f (x) = \frac{1 - x}{( x + 1 ) ^{3}}

x = 2

Solution steps

\frac{1 - x}{( x + 1 ) ^{3}}

Find where

f^{'} (x)

is equal to zero or undefined

x = 2, x = - 1

Identify critical points not in

f (x)

domain

Domain of

\frac{1 - x}{( x + 1 ) ^{3}} : x < - 1 or x > - 1

\frac{1 - x}{( x + 1 ) ^{3}}

is not defined at

x = - 1

, therefore:

x = 2

f (x) = (x - 9) e^{x}

f (x) = x^{\frac{2}{3}} (1 - x)

x^{\frac{3}{2}} (3 x + 10)

f (x) = 3 + 2 x - x^{2}

\frac{x ^{2}}{x ^{2} + 2 x - 15}

What is the critical f(x)=(1-x)/((x+1)^3) ?
The critical f(x)=(1-x)/((x+1)^3) is x=2