What is the critical f(x)=(3x^2)/(x-7) ?

The critical f(x)=(3x^2)/(x-7) is x=0,x=14

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critical f(x)=(3x^2)/(x-7)

critical points

f (x) = \frac{3 x ^{2}}{x - 7}

x = 0, x = 14

Solution steps

\frac{3 x ^{2}}{x - 7}

Find where

f^{'} (x)

is equal to zero or undefined

x = 0, x = 14, x = 7

Identify critical points not in

f (x)

domain

Domain of

\frac{3 x ^{2}}{x - 7} : x < 7 or x > 7

\frac{3 x ^{2}}{x - 7}

is not defined at

x = 7

, therefore:

x = 0, x = 14

f (x, y) = x^{2} y^{2} - \frac{2}{3} x^{3} - \frac{2}{3} y^{3}

- x^{4} + 8 x^{2} + 2

x^{2} + y^{2} + x^{2} y + 4

f (x) = - 4 x^{3} + 9 x^{2} - 4 x

f (x) = x^{2} - 24 x + 6

What is the critical f(x)=(3x^2)/(x-7) ?
The critical f(x)=(3x^2)/(x-7) is x=0,x=14