What is the critical f(x)=x^3ln(x^2) ?

The critical f(x)=x^3ln(x^2) is x=-sqrt(1/(e^{2/3))},x=sqrt(1/(e^{2/3))}

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critical f(x)=x^3ln(x^2)

critical points

f (x) = x^{3} ln (x^{2})

x = - \frac{1}{e ^{\frac{2}{3}}}, x = \frac{1}{e ^{\frac{2}{3}}}

Solution steps

x^{3} ln (x^{2})

Find where

f^{'} (x)

is equal to zero or undefined

x = - \frac{1}{e ^{\frac{2}{3}}}, x = \frac{1}{e ^{\frac{2}{3}}}, x = 0

Identify critical points not in

f (x)

domain

Domain of

x^{3} ln (x^{2}) : x < 0 or x > 0

x^{3} ln (x^{2})

is not defined at

x = 0

, therefore:

x = - \frac{1}{e ^{\frac{2}{3}}}, x = \frac{1}{e ^{\frac{2}{3}}}

f (x) = \frac{5}{x + 2} - 1

2 y^{3} + 6 y x^{2} - 3 x^{3} - 150 y

\frac{7 x}{x ^{2} - 9}

y = \frac{2 - x ^{2}}{3 x ^{2} - 1}

x 7 - x

What is the critical f(x)=x^3ln(x^2) ?
The critical f(x)=x^3ln(x^2) is x=-sqrt(1/(e^{2/3))},x=sqrt(1/(e^{2/3))}