What is the critical x/(x^2+10x+24) ?

The critical x/(x^2+10x+24) is x=-2sqrt(6),x=2sqrt(6)

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critical x/(x^2+10x+24)

critical points

\frac{x}{x ^{2} + 10 x + 24}

x = - 26, x = 26

Solution steps

\frac{x}{x ^{2} + 10 x + 24}

Find where

f^{'} (x)

is equal to zero or undefined

x = - 26, x = 26, x = - 6, x = - 4

Identify critical points not in

f (x)

domain

Domain of

\frac{x}{x ^{2} + 10 x + 24} : x < - 6 or - 6 < x < - 4 or x > - 4

\frac{x}{x ^{2} + 10 x + 24}

is not defined at

x = - 6, x = - 4

, therefore:

x = - 26, x = 26

f (x) = x - ln (x^{9})

x^{2} - y^{2} 1 - x^{2} - y^{2}

\frac{4 x}{1 + x ^{2}}

f (x) = - 9 x^{2} + 18 x + 6

f (x) = 5 cos^{2} (x), (0, 2 π)

What is the critical x/(x^2+10x+24) ?
The critical x/(x^2+10x+24) is x=-2sqrt(6),x=2sqrt(6)