What is the critical f(x)=((x^3))/((x+1)) ?

The critical f(x)=((x^3))/((x+1)) is x=-3/2 ,x=0

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critical f(x)=((x^3))/((x+1))

critical points

f (x) = \frac{( x ^{3} )}{( x + 1 )}

x = - \frac{3}{2}, x = 0

Solution steps

\frac{x ^{3}}{x + 1}

Find where

f^{'} (x)

is equal to zero or undefined

x = - \frac{3}{2}, x = 0, x = - 1

Identify critical points not in

f (x)

domain

Domain of

\frac{x ^{3}}{x + 1} : x < - 1 or x > - 1

\frac{x ^{3}}{x + 1}

is not defined at

x = - 1

, therefore:

x = - \frac{3}{2}, x = 0

f (x) = 2 x - 4 x^{2}

\frac{- x ^{3} - x + 5}{2 x ^{3} + 3 x ^{2} - 7}

t 4 - t^{2}

f (x) = 12 x^{2} - 144 x + 288

What is the critical f(x)=((x^3))/((x+1)) ?
The critical f(x)=((x^3))/((x+1)) is x=-3/2 ,x=0