What is the critical f(x)=(-9)/((x^2-9)sqrt(x^2-9)) ?

The critical f(x)=(-9)/((x^2-9)sqrt(x^2-9)) is None

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critical f(x)=(-9)/((x^2-9)sqrt(x^2-9))

critical points

f (x) = \frac{- 9}{( x ^{2} - 9 ) x ^{2} - 9}

None

Solution steps

\frac{- 9}{( x ^{2} - 9 ) x ^{2} - 9}

Find where

f^{'} (x)

is equal to zero or undefined

x = - 3, x = 3

Identify critical points not in

f (x)

domain

Domain of

\frac{- 9}{( x ^{2} - 9 ) x ^{2} - 9} : x < - 3 or x > 3

\frac{- 9}{( x ^{2} - 9 ) x ^{2} - 9}

is not defined at

x = - 3, x = 3

, therefore:

None

f (x, y) = x^{2} - 4 x y + y^{2}

f (x) = 4 (x - 4)^{\frac{2}{3}}

\frac{- 2 x}{( 1 + x ^{2} ) ^{2}}

f (x) = 2 x^{3} - 21 x^{2} + 5

f (x) = x^{2} x + 14

What is the critical f(x)=(-9)/((x^2-9)sqrt(x^2-9)) ?
The critical f(x)=(-9)/((x^2-9)sqrt(x^2-9)) is None