What is the critical f(x)=((x+3))/(x^2-5x+6) ?

The critical f(x)=((x+3))/(x^2-5x+6) is x=-3-sqrt(30),x=sqrt(30)-3

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critical f(x)=((x+3))/(x^2-5x+6)

critical points

f (x) = \frac{( x + 3 )}{x ^{2} - 5 x + 6}

x = - 3 - 30, x = 30 - 3

Solution steps

\frac{x + 3}{x ^{2} - 5 x + 6}

Find where

f^{'} (x)

is equal to zero or undefined

x = - 3 - 30, x = 30 - 3, x = 2, x = 3

Identify critical points not in

f (x)

domain

Domain of

\frac{x + 3}{x ^{2} - 5 x + 6} : x < 2 or 2 < x < 3 or x > 3

\frac{x + 3}{x ^{2} - 5 x + 6}

is not defined at

x = 2, x = 3

, therefore:

x = - 3 - 30, x = 30 - 3

f (x) = x^{4} - \frac{3 x ^{2}}{2} - x + \frac{29}{16}

y = 8 - (x + 3)^{2}

f (x, y) = y^{3} + 3 x^{2} - 6 x y - 9 y - 2

x x^{2} + 9

y = (x + 1)^{2} (x - 2)^{2}

What is the critical f(x)=((x+3))/(x^2-5x+6) ?
The critical f(x)=((x+3))/(x^2-5x+6) is x=-3-sqrt(30),x=sqrt(30)-3