What is the critical f(x)=((3+x)^2(4-x))/(x^2+7) ?

The critical f(x)=((3+x)^2(4-x))/(x^2+7) is x=-3,x\approx 0.80968…

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critical f(x)=((3+x)^2(4-x))/(x^2+7)

critical points

f (x) = \frac{( 3 + x ) ^{2} ( 4 - x )}{x ^{2} + 7}

x = - 3, x \approx 0.80968 \dots

Solution steps

\frac{( 3 + x ) ^{2} ( 4 - x )}{x ^{2} + 7}

Find where

f^{'} (x)

is equal to zero or undefined

x = - 3, x \approx 0.80968 \dots

Identify critical points not in

f (x)

domain

Domain of

\frac{( 3 + x ) ^{2} ( 4 - x )}{x ^{2} + 7} : - \infty < x < \infty

All critical points are in domain

x = - 3, x \approx 0.80968 \dots

f (x) = 2 x - x^{2}

f (x) = x^{2} + 8 x + 19

f (x) = x^{3} + 2 x^{2} - 4 x

(x - y) (4 - x y)

What is the critical f(x)=((3+x)^2(4-x))/(x^2+7) ?
The critical f(x)=((3+x)^2(4-x))/(x^2+7) is x=-3,x\approx 0.80968…