What is the extreme f(x,y)=(x^2y)/(2x-y) ?

The extreme f(x,y)=(x^2y)/(2x-y) is None

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extreme f(x,y)=(x^2y)/(2x-y)

extreme points

f (x, y) = \frac{x ^{2} y}{2 x - y}

None

Solution steps

Find the critical points:

None

\frac{x ^{2} y}{2 x - y}

has no critical points, therefore there are no extreme points

None

f (x) = (x + 4) (x - 5)^{2}

f (x) = 2 + x - 2 x^{2} - x^{3}

y = \frac{x}{x ^{2} - 4}

y = x^{3} - 3 x^{2} - 9 x + 20

What is the extreme f(x,y)=(x^2y)/(2x-y) ?
The extreme f(x,y)=(x^2y)/(2x-y) is None