What is the critical f(x)= 2/(x^2-3x+2) ?

The critical f(x)= 2/(x^2-3x+2) is x= 3/2

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critical f(x)= 2/(x^2-3x+2)

critical points

f (x) = \frac{2}{x ^{2} - 3 x + 2}

x = \frac{3}{2}

Solution steps

\frac{2}{x ^{2} - 3 x + 2}

Find where

f^{'} (x)

is equal to zero or undefined

x = \frac{3}{2}, x = 1, x = 2

Identify critical points not in

f (x)

domain

Domain of

\frac{2}{x ^{2} - 3 x + 2} : x < 1 or 1 < x < 2 or x > 2

\frac{2}{x ^{2} - 3 x + 2}

is not defined at

x = 1, x = 2

, therefore:

x = \frac{3}{2}

f (x) = - 4 x^{2} + 5 x - 3, - 4 \leq x \leq 4

f (x, y) = 4 x^{3} + y^{2} - 12 x^{2} - 8 y + 9 x - 2

f (x) = ∣ x ∣^{x}

f (x, y) = x y - x^{2} - y^{2} - 8 x - 2 y + 4

f (x, y) = x^{2} - 3 y^{2} - 8 x + 9 y + 3 x y

What is the critical f(x)= 2/(x^2-3x+2) ?
The critical f(x)= 2/(x^2-3x+2) is x= 3/2