What is the critical f(x)=(ln(x^2))/x ?

The critical f(x)=(ln(x^2))/x is x=-e,x=e

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critical f(x)=(ln(x^2))/x

critical points

f (x) = \frac{ln ( x ^{2} )}{x}

x = - e, x = e

Solution steps

\frac{ln ( x ^{2} )}{x}

Find where

f^{'} (x)

is equal to zero or undefined

x = - e, x = e, x = 0

Identify critical points not in

f (x)

domain

Domain of

\frac{ln ( x ^{2} )}{x} : x < 0 or x > 0

\frac{ln ( x ^{2} )}{x}

is not defined at

x = 0

, therefore:

x = - e, x = e

(x^{2} - 6 x)^{\frac{2}{3}}

f (x) = x ∣ x ∣

f (x) = x^{3} + 3 x^{2} - 24 x + 12

f (x) = (x - 4)^{2} + 1 + 3

f (x, y) = 2 x + y - x y + 190

What is the critical f(x)=(ln(x^2))/x ?
The critical f(x)=(ln(x^2))/x is x=-e,x=e