What is the critical f(x)=(x^2+3)/(x^3-9) ?

The critical f(x)=(x^2+3)/(x^3-9) is x\approx-1.57000…,x=0

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critical f(x)=(x^2+3)/(x^3-9)

critical points

f (x) = \frac{x ^{2} + 3}{x ^{3} - 9}

x \approx - 1.57000 \dots, x = 0

Solution steps

\frac{x ^{2} + 3}{x ^{3} - 9}

Find where

f^{'} (x)

is equal to zero or undefined

Identify critical points not in

f (x)

domain

Domain of

\frac{x ^{2} + 3}{x ^{3} - 9}

is not defined at

, therefore:

x \approx - 1.57000 \dots, x = 0

f (x, y) = \frac{3 x}{64 + x ^{2} + y ^{2}}

f (x) = e^{a x^{2} + 4}

\frac{x ^{2}}{1 + x ^{2}}

\frac{x - 4}{x ^{2}}

f (x) = \frac{( x ^{2} - 4 )}{1 - x ^{2}}

What is the critical f(x)=(x^2+3)/(x^3-9) ?
The critical f(x)=(x^2+3)/(x^3-9) is x\approx-1.57000…,x=0