What is the critical f(x)= x/(1x^2-1) ?

The critical f(x)= x/(1x^2-1) is None

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critical f(x)= x/(1x^2-1)

critical points

f (x) = \frac{x}{1 x ^{2} - 1}

None

Solution steps

\frac{x}{1 \cdot x ^{2} - 1}

Find where

f^{'} (x)

is equal to zero or undefined

x = - 1, x = 1

Identify critical points not in

f (x)

domain

Domain of

\frac{x}{1 x ^{2} - 1} : x < - 1 or - 1 < x < 1 or x > 1

\frac{x}{1 x ^{2} - 1}

is not defined at

x = - 1, x = 1

, therefore:

None

f (x) = x^{2} + 3 x - 8

f (x, y) = 2 x^{2} + x y^{3} - 6 x y + 5 x + 2

f (x) = 32 x^{2} e^{- 0.125 x}

f (x) = x^{2} + x y + y^{2} - 6 x + 2

f (x) = 2 x^{2} - 5 x y + 3 y^{4} + 5