What is the critical f(x)=9x+9x^{-1} ?

The critical f(x)=9x+9x^{-1} is x=-1,x=1

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critical f(x)=9x+9x^{-1}

critical points

f (x) = 9 x + 9 x^{- 1}

x = - 1, x = 1

Solution steps

9 x + 9 x^{- 1}

Find where

f^{'} (x)

is equal to zero or undefined

x = - 1, x = 1, x = 0

Identify critical points not in

f (x)

domain

Domain of

9 x + 9 x^{- 1} : x < 0 or x > 0

9 x + 9 x^{- 1}

is not defined at

x = 0

, therefore:

x = - 1, x = 1

\frac{4 e ^{4 x}}{3 x - 15}

2 x^{3} - 15 x^{2} + y^{3} + 6 y^{2}

- 7 (x + 3)^{2} (x - 1) (x - 5)

f (x) = \frac{( 5 x ^{2} )}{x ^{2} + 16}

(x^{2} - 3)^{2}