What is the critical f(x)= x/(x^2+12x+32) ?

The critical f(x)= x/(x^2+12x+32) is x=-4sqrt(2),x=4sqrt(2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

critical f(x)= x/(x^2+12x+32)

critical points

f (x) = \frac{x}{x ^{2} + 12 x + 32}

x = - 42, x = 42

Solution steps

\frac{x}{x ^{2} + 12 x + 32}

Find where

f^{'} (x)

is equal to zero or undefined

x = - 42, x = 42, x = - 8, x = - 4

Identify critical points not in

f (x)

domain

Domain of

\frac{x}{x ^{2} + 12 x + 32} : x < - 8 or - 8 < x < - 4 or x > - 4

\frac{x}{x ^{2} + 12 x + 32}

is not defined at

x = - 8, x = - 4

, therefore:

x = - 42, x = 42

y = 2 x + 3

f (θ) = 10 cos (θ) + 5 sin^{2} (θ)

f (x) = \frac{6 x}{3 + x ^{2}}

y = I n X

y = \frac{1}{x ^{2} - 4}

What is the critical f(x)= x/(x^2+12x+32) ?
The critical f(x)= x/(x^2+12x+32) is x=-4sqrt(2),x=4sqrt(2)