What is the critical-(2(x^2-1))/(x^2-4) ?

The critical-(2(x^2-1))/(x^2-4) is x=0

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critical-(2(x^2-1))/(x^2-4)

critical points

- \frac{2 ( x ^{2} - 1 )}{x ^{2} - 4}

x = 0

Solution steps

- \frac{2 ( x ^{2} - 1 )}{x ^{2} - 4}

Find where

f^{'} (x)

is equal to zero or undefined

x = 0, x = - 2, x = 2

Identify critical points not in

f (x)

domain

Domain of

- \frac{2 ( x ^{2} - 1 )}{x ^{2} - 4} : x < - 2 or - 2 < x < 2 or x > 2

- \frac{2 ( x ^{2} - 1 )}{x ^{2} - 4}

is not defined at

x = - 2, x = 2

, therefore:

x = 0

f (x) = \frac{x}{2 x ^{2} + 1}

f (x, y) = (3 x + 4 x^{3}) (y^{2} + 2 y)

x^{3} - 2 x

f (x, y) = x^{2} - x^{2} y^{2} + y^{2}

f (x) = 21 x y e^{- x^{2} - y^{2}}

What is the critical-(2(x^2-1))/(x^2-4) ?
The critical-(2(x^2-1))/(x^2-4) is x=0