What is the critical f(x)=(4x)/(x^2-25) ?

The critical f(x)=(4x)/(x^2-25) is None

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critical f(x)=(4x)/(x^2-25)

critical points

f (x) = \frac{4 x}{x ^{2} - 25}

None

Solution steps

\frac{4 x}{x ^{2} - 25}

Find where

f^{'} (x)

is equal to zero or undefined

x = - 5, x = 5

Identify critical points not in

f (x)

domain

Domain of

\frac{4 x}{x ^{2} - 25} : x < - 5 or - 5 < x < 5 or x > 5

\frac{4 x}{x ^{2} - 25}

is not defined at

x = - 5, x = 5

, therefore:

None

f (x) = 1 - e^{x^{2} + 4 x}, - 4 \leq x \leq 0

x^{3} - 3 x + 3 x y^{2}

\frac{4 x ^{5}}{5} - \frac{5 x ^{4}}{4} + 4 x - 1

f (x) = x x^{2} + 36

f (x) = e^{2 x}

What is the critical f(x)=(4x)/(x^2-25) ?
The critical f(x)=(4x)/(x^2-25) is None