What is the critical f(x)=(x^2-4)/(x^2-2x) ?

The critical f(x)=(x^2-4)/(x^2-2x) is None

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critical f(x)=(x^2-4)/(x^2-2x)

critical points

f (x) = \frac{x ^{2} - 4}{x ^{2} - 2 x}

None

Solution steps

\frac{x ^{2} - 4}{x ^{2} - 2 x}

Find where

f^{'} (x)

is equal to zero or undefined

x = 0

Identify critical points not in

f (x)

domain

Domain of

\frac{x ^{2} - 4}{x ^{2} - 2 x} : x < 0 or 0 < x < 2 or x > 2

\frac{x ^{2} - 4}{x ^{2} - 2 x}

is not defined at

x = 0

, therefore:

None

y = x^{3}

3 x^{2} - 4 x^{3}

5 + 54 x - 2 x^{3}

f (x, y) = 2 x^{3} - 6 x + 3 y^{2}

\frac{1}{X ^{2}}

What is the critical f(x)=(x^2-4)/(x^2-2x) ?
The critical f(x)=(x^2-4)/(x^2-2x) is None