What is the critical (ω^2+2ω+1)/(3ω-5) ?

The critical (ω^2+2ω+1)/(3ω-5) is ω=-1,ω= 13/3

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critical (ω^2+2ω+1)/(3ω-5)

critical points

\frac{ω ^{2} + 2 ω + 1}{3 ω - 5}

ω = - 1, ω = \frac{13}{3}

Solution steps

\frac{ω ^{2} + 2 ω + 1}{3 ω - 5}

Find where

f^{'} (ω)

is equal to zero or undefined

ω = - 1, ω = \frac{13}{3}, ω = \frac{5}{3}

Identify critical points not in

f (ω)

domain

Domain of

\frac{ω ^{2} + 2 ω + 1}{3 ω - 5} : ω < \frac{5}{3} or ω > \frac{5}{3}

\frac{ω ^{2} + 2 ω + 1}{3 ω - 5}

is not defined at

ω = \frac{5}{3}

, therefore:

ω = - 1, ω = \frac{13}{3}

f (x) = x^{2} + 2 x y + 2 y^{2} - 6 x + 10 y + 4

3 x^{2} + 2 x + 5

f (x) = 4 x^{5} - 12 x^{3} + 3

f (x) = \frac{3 I n ( x )}{4 ^{x}}

What is the critical (ω^2+2ω+1)/(3ω-5) ?
The critical (ω^2+2ω+1)/(3ω-5) is ω=-1,ω= 13/3