What is the critical f(x)=(2x+1)/(x^2+6x+5) ?

The critical f(x)=(2x+1)/(x^2+6x+5) is x=-2,x=1

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critical f(x)=(2x+1)/(x^2+6x+5)

critical points

f (x) = \frac{2 x + 1}{x ^{2} + 6 x + 5}

x = - 2, x = 1

Solution steps

\frac{2 x + 1}{x ^{2} + 6 x + 5}

Find where

f^{'} (x)

is equal to zero or undefined

x = - 2, x = 1, x = - 5, x = - 1

Identify critical points not in

f (x)

domain

Domain of

\frac{2 x + 1}{x ^{2} + 6 x + 5} : x < - 5 or - 5 < x < - 1 or x > - 1

\frac{2 x + 1}{x ^{2} + 6 x + 5}

is not defined at

x = - 5, x = - 1

, therefore:

x = - 2, x = 1

f (x) = x^{4} - 2 x^{3} - 2 x^{2}

f (x, y) = 4 x y - x^{2} - y^{2} - 14 x + 4 y + 10

f (x) = - 2 x^{2} + 2 x y - 3 y^{2} + 10 x + 10 y + 15

f (x) = sin (2 x), 0 \leq x \leq 2 π

\frac{1}{1 - x ^{2}}

What is the critical f(x)=(2x+1)/(x^2+6x+5) ?
The critical f(x)=(2x+1)/(x^2+6x+5) is x=-2,x=1