What is the extreme f(x)=3x^3-18x^2+100 ?

The extreme f(x)=3x^3-18x^2+100 is Maximum(0,100),Minimum(4,4)

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extreme f(x)=3x^3-18x^2+100

extreme points

f (x) = 3 x^{3} - 18 x^{2} + 100

Maximum (0, 100), Minimum (4, 4)

Solution steps

f^{'} (x) = 9 x^{2} - 36 x

Find intervals:

Increasing

: - \infty < x < 0,

Decreasing

: 0 < x < 4,

Increasing

: 4 < x < \infty

Plug

x = 0

into

3 x^{3} - 18 x^{2} + 100 : 100

Maximum (0, 100)

Plug

x = 4

into

3 x^{3} - 18 x^{2} + 100 : 4

Minimum (4, 4)

Maximum (0, 100), Minimum (4, 4)

2 x + 3 y = 18

f (x) = 3 x^{4} - 30 x^{2} + 27

f (x) = 3 x + 10

\frac{2 x}{x - 4}

- 3 x^{2} + 3 x - 2

What is the extreme f(x)=3x^3-18x^2+100 ?
The extreme f(x)=3x^3-18x^2+100 is Maximum(0,100),Minimum(4,4)