What is the critical (5-x)/(x^2-3x) ?

The critical (5-x)/(x^2-3x) is x=5-sqrt(10),x=5+sqrt(10)

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critical (5-x)/(x^2-3x)

critical points

\frac{5 - x}{x ^{2} - 3 x}

x = 5 - 10, x = 5 + 10

Solution steps

\frac{5 - x}{x ^{2} - 3 x}

Find where

f^{'} (x)

is equal to zero or undefined

x = 5 - 10, x = 5 + 10, x = 0, x = 3

Identify critical points not in

f (x)

domain

Domain of

\frac{5 - x}{x ^{2} - 3 x} : x < 0 or 0 < x < 3 or x > 3

\frac{5 - x}{x ^{2} - 3 x}

is not defined at

x = 0, x = 3

, therefore:

x = 5 - 10, x = 5 + 10

f (x) = 3 x^{4} - 54 x^{2} + 4 y^{3} - 12 y + 4

6 x - 8 x

f (x) = sin (2 x) - sin (x)

f (x) = 8 x + sin (8 x)

f (x) = \frac{1}{6} x^{6} + \frac{5}{4} x^{4} - 10 x^{2}

What is the critical (5-x)/(x^2-3x) ?
The critical (5-x)/(x^2-3x) is x=5-sqrt(10),x=5+sqrt(10)