What is the critical (x^2-7)/(x-3) ?

The critical (x^2-7)/(x-3) is x=3-sqrt(2),x=3+sqrt(2)

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critical (x^2-7)/(x-3)

critical points

\frac{x ^{2} - 7}{x - 3}

x = 3 - 2, x = 3 + 2

Solution steps

\frac{x ^{2} - 7}{x - 3}

Find where

f^{'} (x)

is equal to zero or undefined

x = 3 - 2, x = 3 + 2, x = 3

Identify critical points not in

f (x)

domain

Domain of

\frac{x ^{2} - 7}{x - 3} : x < 3 or x > 3

\frac{x ^{2} - 7}{x - 3}

is not defined at

x = 3

, therefore:

x = 3 - 2, x = 3 + 2

Y (x) = - 1 x + 7, (5, - 8)

f (x) = 9 x^{2} - x^{3} - 3

f (x) = \frac{4}{3 + x}

f (x) = 16 - x^{2}

f (x) = - x^{2} - 4 x + 4

What is the critical (x^2-7)/(x-3) ?
The critical (x^2-7)/(x-3) is x=3-sqrt(2),x=3+sqrt(2)