What is the critical f(x)=(3x-2)/(2sqrt(x-1)) ?

The critical f(x)=(3x-2)/(2sqrt(x-1)) is x= 4/3

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critical f(x)=(3x-2)/(2sqrt(x-1))

critical points

f (x) = \frac{3 x - 2}{2 x - 1}

x = \frac{4}{3}

Solution steps

\frac{3 x - 2}{2 x - 1}

Find where

f^{'} (x)

is equal to zero or undefined

x = \frac{4}{3}, x = 1

Identify critical points not in

f (x)

domain

Domain of

\frac{3 x - 2}{2 x - 1} : x > 1

\frac{3 x - 2}{2 x - 1}

is not defined at

x = 1

, therefore:

x = \frac{4}{3}

f (x) = (6 - x) (6 - y) (x + y - 6)

f (x) = x^{3} - 8 x + 1

f (x) = \frac{x ^{3} - 8}{x ^{2} - 4}

f (x) = 4 x^{4} - 4 x^{2}

f (x) = 4 x + 2

What is the critical f(x)=(3x-2)/(2sqrt(x-1)) ?
The critical f(x)=(3x-2)/(2sqrt(x-1)) is x= 4/3