What is the critical f(x)=-(4x)/((x^2-1)^2) ?

The critical f(x)=-(4x)/((x^2-1)^2) is None

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critical f(x)=-(4x)/((x^2-1)^2)

critical points

f (x) = - \frac{4 x}{( x ^{2} - 1 ) ^{2}}

None

Solution steps

- \frac{4 x}{( x ^{2} - 1 ) ^{2}}

Find where

f^{'} (x)

is equal to zero or undefined

x = - 1, x = 1

Identify critical points not in

f (x)

domain

Domain of

- \frac{4 x}{( x ^{2} - 1 ) ^{2}} : x < - 1 or - 1 < x < 1 or x > 1

- \frac{4 x}{( x ^{2} - 1 ) ^{2}}

is not defined at

x = - 1, x = 1

, therefore:

None

f (x) = 2 x 16 - x^{2}

\frac{7 x}{x ^{2} - 49}

f (x) = 4 x + \frac{1}{x}

f (x, y) = e^{x + y} - x e^{2 y}

f (x) = e^{x^{2} - 2 x - 1}

What is the critical f(x)=-(4x)/((x^2-1)^2) ?
The critical f(x)=-(4x)/((x^2-1)^2) is None