What is the critical f(x)=((x^2-1))/(x^3) ?

The critical f(x)=((x^2-1))/(x^3) is x=-sqrt(3),x=sqrt(3)

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critical f(x)=((x^2-1))/(x^3)

critical points

f (x) = \frac{( x ^{2} - 1 )}{x ^{3}}

x = - 3, x = 3

Solution steps

\frac{x ^{2} - 1}{x ^{3}}

Find where

f^{'} (x)

is equal to zero or undefined

x = - 3, x = 3, x = 0

Identify critical points not in

f (x)

domain

Domain of

\frac{x ^{2} - 1}{x ^{3}} : x < 0 or x > 0

\frac{x ^{2} - 1}{x ^{3}}

is not defined at

x = 0

, therefore:

x = - 3, x = 3

f (x) = x^{3} + x + 1

f (x) = x^{3} + x - 2

f (x, y) = x^{2} y - 4 x y + 3 x y^{2}

y = \frac{6 e ^{x}}{6 e ^{x} + 6}

2 x^{3} - 6 x^{2} - 48 x + 7

What is the critical f(x)=((x^2-1))/(x^3) ?
The critical f(x)=((x^2-1))/(x^3) is x=-sqrt(3),x=sqrt(3)